Question

Calculate the degree of dissociation of acetic acid if its molar conductivity is 39.05

Answer 1

The degree of dissociation is give by the following relation:

α  =  Λm / Λo

Where α is the degree of dissociation, Λm  is the molar conductivity and Λo  is the molar conductivity at infinite dilution.

We have given

λ0H+ = 349.6 S cm2mol-1 

and

λ0(CH3COO-) = 40.9 S cm2mol-1

then,

λ0CH3COOH  =  349.6 + 40.9 = 390.5


Now, degree of dissociation (α) is:

= 39.05 / 390.5

= 0.1