calculate the degree of dissociation of weak electrolyte AB inaqeous solution if Tf=0.20k for 0.1 molality solution kf=1.86
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Answer:
Tf=i×Kf×m
0.20=i×1.86×0.1
i=0.20/0.86
i=approximately 1
Explanation:
- for weak electrolyte degree of dissociation is nearly equal to vant-off factor
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