Question

Calculate the degree of hardness of a sample water containing 6mg of MgSO4 per kilogram of water

Answer 1

Answer:

Explanation:

1g−mole or 120gMgSO4has=1g−mole or 100gCaCO3

∴6×10−3gMgSO4has=100×6×10−3120

=5×10−3gCaCO3

Thus 1000g of water contains MgSO4 equivalent to 5×10−3gCaCO3

∴106g water contains =5×10−31000×106

5gofCaCO3