calculate the degree of hydrolysis of 0.1 m ch3coonh4 solution whose hydrolysis constant is 4 *10^-10
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Answer:
K
b
=K
a
=1.8×10
−5
Thus,
(1−α)
2
α
2
=
1.8×10
−5
×1.8×10
−5
1.0×10
−14
or
1−α
α
=
1.8×10
−5
×1.8×10
−5
1.0×10
−14
1−α
α
=
1.8
10
−2
=
180
1
∴ α=0.55×10
−2
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