Question

Calculate the density of 3.60 M H2SO4, solution that is 98% by mass.​

Answer 1

Explanation:

3.6 M=3.6 moles lit^-1

Let us assume the volume of solution is

1 litre.

So there are 3.6 moles

no. of moles=wt/molecular wt

3.6=wt/98gm

weight=3.6×98gm

weight=352.8 gm

98% by mass H2SO4 solution

98 gm of H2SO4------->100 gm solution

1 gm H2SO4-------->100/98 gm solution

352.8 gm H2SO4--->100/98×352.8 gm soln

352.8gm H2SO4--->1216 gm solution

density of solution=1216 gm/1 litre

density of solution=1216/1000ml

density of solution=1.216 gm/ml