calculate the density of ice in g/cm^3 when 230 kg of ice occupies 0.25m^3 volume
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Answered by
10
Answer:
Applying the equation PV = nST,
V = n/P × S × T
Given n = 1, P = 1 atm, S = 0.821 and T = 273 K
V = 1/1 × 0.0821 × 273 = 22.4 litre
Answered by
30
Explanation:
mass=230kg
volume=0.25m³
density =mass/ volume
=230/25×100=920kg/m³
=920×1000g/10000cm³=92g/cm³
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