Question

Calculate the density of pbS crystal (fcc) if the edge length is 500pm and atomic mass of pb=207.2, S=32

Answer 1

Answer:

Given: PbS forms FCC structure. a = 500 pm = 5 × 10⁻⁸ cm. NA = 6.022 × 10²³ Atomic mass of Pb = 207.2 and S = 32.

To Find: The density (d) of PbS crystal.

Calculation: - Molar mass of PbS = 207.2 + 32 = 239.2 gm. - For FCC, z = 4. - V = a³ = (5 × 10⁻⁸)³ ...

⇒ d = 12.71 gm/cm³

- So, the density of PbS is 12.71 gm/cm³.

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