Question

Calculate the depression in freezing poimt of 10 gm of 2 chlororbutanoic acid ks added to 250 gm of water

Answer 1

∆T=kf×m

∆T is depression in freezing point

Kf =cryoscopic constant = 1.86 k kg / mol

m is molality

∆T= 10×1000/122.5×25

∆T= 10000/1225×25