calculate the depth below the surface of water at which the pressure due to the weight of water equals 1.00 atm.
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We begin by solving the equation P =hρg for depth h :
h=P/ρg.
Then we take P to be 1.00 atm and ρ to be the density of the water that creates the pressure.
Solution:
Entering the known values into the expression for h gives
h=1.01×105N/m2(1.00×103kg/m3)(9.80m/s2)= 10.3m.
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Answer:
The answer is 10.3m.
Explanation:
we know:
density of water(d)=1000kg/m^3
gravity(g)=9.8m/s^2
pressure(p)=1atm=1.01×10^5pa ==>(given)
As we know pressure(p)=hdg,
then,
or,1.01×10^5=h×1000×9.8
or,h=1.01×10^5/(9.8×1000)
Therefore, h=10.3m.
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