Question

Calculate the depth in the ocean at which the pressure is three times atmospheric pressure. Atmospheric pressure is 1.013 × 105 Pa. The acceleration of gravity is 9.81 m/s2 and the density of sea water is 1025 kg/m3 . Answer in units of m.

Answer 1

Answer:

Use formula

Pd = 3 Patm

Patm + pgh = 3Patm

pgh = 2 Patm

Patm = 1.013 × 10^5Pa

h = depth

h = 2.016 × 10^5 /10.05 × 10^3

h = 20.15 m (Approx)

Answer 2

The depth in the ocean is 20.15 m.

Explanation:

Given that,

Pressure $P= 3 P_{atm}$

Atmospheric pressure $P_{atm}=1.013\times10^{5}\ Pa$

Acceleration of gravity = 9.81 m/s²

Density of sea water = 1025 kg/m³

We need to calculate the depth in the ocean

Using formula of depth

$h=\dfrac{P-P_{0}}{\rho g}$

Where, $P_{atm}$ =Atmospheric pressure

P= total pressure

g = acceleration due to gravity

$\rho$ = density of sea water

Put the value into the formula

$h=\dfrac{3\times1.013\times10^{5}-1.013\times10^{5}}{1025\times9.81}$

$h=20.15\ m$

Hence, The depth in the ocean is 20.15 m.

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Topic : atmospheric pressure

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