Question

Calculate the depth in the ocean at which the
pressure is three times atmospheric pressure.
Atmospheric pressure is 1.013 × 105 Pa. The
acceleration of gravity is 9.81 m/s
2
and the
density of sea water is 1025 kg/m3
.
Answer in units of m.

Answer 1

If P(a) is the atmospheric pressure then the pressure below the surface of water of density k, under depth h is given by

P = P(a) + hkg

3P(a) = P(a) + hkg

2P(a) = hkg

h = 2 x P(a)/(kg)

on substituting values of atmospheric pressure, density of water and gravity's acceleration, we get

h = 20.1 m

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