Question

Calculate the design rate of super elevation on a 3 degree horizontal curve for a narrow gauge track, if design velocity on the curve is 70 km/h.

Answer 1

Answer:

Rate of Super elevation is 0.0512

Explanation:

This question is related to civil engineering specially railway design engineering so the formula that is used to calculate rate of super elevation for a narrow guage track is given as;

Rate of Super elevation = GV^2/127R

G = 0.762 for narrow guage track

For horizontal curve of 3 degrees;

R = 1270/3

R = 573.33

e = GV^2/127R

e = (0.762 x 70 x 70)/(127 x 573.33)

e = 0.0512

Rate of Super elevation is 0.0512

Answer 2

Explanation:

how you find the value of R