Question

Calculate the difference between compound interest and simple interest on a

sum of Rs. 500000 at 8% p.a. for 2 years.​

Answer 1

Step-by-step explanation:

The answer is 3,200.

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Answer 2

$\Huge\boxed {r.s=3200}$

$\Large{\textsf{\textbf{\underline{\underline{Given\::}}}}}$

$p = rs.500000$

$r = 8\%p.a.$

$t = 2 \: years.$

$\Large{\textsf{\textbf{\underline{\underline{To.find\::}}}}}$

$●diffrence \: between \\ \: ci \: and \: si$

$\Large{\textsf{\textbf{\underline{\underline{formulas.used\::}}}}}$

$si = \frac{prt}{100}$

$A = p \: (1 + \frac{r}{100} )t$

$c.i = a-p$

$\Large{\textsf{\textbf{\underline{\underline{solusion\::}}}}}$

${\bf{1.case\::}}$

$➣to \: find \: s.i.$

$➣we \: know, \:$

$➣s.i. = \frac{p \times r \times t}{100}$

$➣s.i. = \frac{500000 \times 8 \times 2}{100}$

$\small{\textsf{\textbf{\underline{\underline{ ➣s.i = 80000\::}}}}}$

${\bf{2.case\::}}$

$➣to \: find \: ci,$

$➣we \: know, \:$

$➣A = p(1 + \frac{r}{100} )t$

$➣a = 500000(1 + \frac{8}{100} ) {}^{2}$

$➣a = 500000(100 + \frac{8}{100} ) {}^{2}$

$➣a = 500000( \frac{108}{100} ) {}^{2}$

$➣a = 500000 \times \frac{108}{100} \times \frac{108}{100}$

$\small{\textsf{\textbf{\underline{\underline{➣A = 583200\::}}}}}$

${\bf{3.case\::}}$

$➣to.find.c.i$

$➣we.know. c.i = A - p$

$➣c.i = 583200 - 500000$

$\small{\textsf{\textbf{\underline{\underline{➣c.i = 83200\::}}}}}$

$\small{\textsf{\textbf{\underline{\underline{now.finding.the.diffrence.between.ci.and.si\::}}}}}$

$➣c.i = 83200$

$➣s.i = 80000$

$➣difference = r.s (83200 - 80000)$

$\Large{\textsf{\textbf{\underline{\underline{➣r.s = 3200\::}}}}}$

$\Large{\textsf{\textbf{\underline{\underline{form.the.soluaion\::}}}}}$

$●p = principal \\ ●r = rate \: of \: interest \\ ●t = time \\ ●si = simple \: interest \\ ●ci = compound \: interest \\ ●a = amount$