calculate the difference between the compound interest and the simple interest on rupees 12000 at 9% per annum in 2 years
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Answer:
SI = PRT/100
= 12000×9×2/100=2160
CI=P[(1+R/100)^n-1]
=12000[(1+9/100)^2-1]
=12000[(109/100)^2-1]
=12000[11881/10000-1]
=12000[1881/10000]
= 12000×1881/10000
=12×1881/10=2257.2
Difference=2257.2-2160
=97.2
himadrishekhar10:
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