Question

calculate the difference between the compound interest and the simple interest on rupees 7500 in 2 years at 8% per annum​

Answer 1

Answer:

difference will be 48 rupees

Step-by-step explanation:

simple interest:7500×2×8%

=1200

compound interest will be:

7500(1+8/100)^2-7500

=7500(1.08)^2-7500

=7500×1.1664-7500

=8748-7500

=1248

so,difference will be,(1248-1200)=48

plz mark it as brainliest answer

Answer 2

$\sf\green{Answer :-}$

➪The difference between the compound interest and simple interest is 12.

$\mathfrak\blue{Full \: Solution :-}$

★ Given :-

➙Principal = Rs 7,500

➙Rate = 8 % (yearly)

➙Rate = 4 % (In 6 month)

➙Time = 1 year = 2 (six month)

Simple interest in 1 year

$\sf{= > \frac{p \times r \times t}{100} = > \frac{7500 \times 8 \times 1}{100} = > 600 \: rupees}$

Interest in 1st six month

$\sf{= > \frac{p \times r \times t}{100} = > \frac{7500 \times 4 \times 1}{100} = > 300 \: rupees}$

New Principal amount

$\sf{=> 7,500+300=7,800 Rs}$

Interest in 1st six month

$\sf{= > \frac{7800 \times 4 \times 1}{100} = > 312 \: rupees}$

$\fbox\red{Compound interest = 300+312= Rs.612}$

The difference between the compound interest and simple interest = $\bold{612-600=12}$