Question

Calculate the difference between two specific heats of 1 g of nitrogen. Given molecular weight of nitrogen = 28 and J = 4.2 x 10⁷ erg cal-1.​

Answer 1

Molecular weight of Helium = M = 4  Universal Gas Constant, R = 8.31J | mole | K 

Cp - Cv = 7 Molecular mass, M = 4 R = 8.31 J mol-1 K-1 Cp - Cv = R/J = R/MJ = (8.31/4 x 4.186) = 0.496 cal g-1 K-1.

Answer 2

Answer:

The difference between two specific heats of 1g of nitrogen is 0.07066 calmol⁻¹K⁻¹.

Explanation:

Given,

wieght of nitrogen, w = 1g

Molar mass of nitrogen, M = 28

Specific heat at constant Pressure = Cp

Specific heat at constant Volume = Cv

Universal gas constant, R = 8.31 Jmol⁻¹K⁻¹

J = 4.2×10⁷ erg cal⁻¹ = 4.2 Jcal⁻¹

Now, for 1 mole of gas

Cv - Cp = mR/J = wR/MJ

where,

m = number of moles

R = universal gas constant

J = energy

So, Cp - Cv = 1×8.31 /28×4.2

Cp - Cv = 0.07066 calmol⁻¹K⁻¹

Hence, the difference between two specific heats of 1g of nitrogen is 0.07066 calmol⁻¹K⁻¹.

To learn more about specific heats, click on the link below:

https://brainly.in/question/1141811

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https://brainly.in/question/839829

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