Question

Calculate the difference in temperatures between two sides of an iron plate 20 mm thick, when heat is conducted at the
rateof 6×10^5 cal/min m². (K for the metal is 0.2 cal/s cm K.)​

Answer 1

Answer:

10 C

Explanation:

Given :

Δ x = 20 mm = 20 × 10⁻³ m

= > Δ Q / Δ t = 6 × 10⁵ cal min m²

K = 0.2 cal sec cm

K in term of Joule :

= > K = 0.2 × 4.2 / 10⁻² J / sec / m / K

We know :

Δ T / Δ x = ( Δ Q / Δ t ) / K A

= > Δ T = ( Δ Q / Δ t ) Δ x / K A

Putting values here we get :

= > Δ T = (  6 × 10⁵ ) × 4.2 × 20 × 10⁻³ × 10⁻² / 60 ×  0.2 × 4.2

= > Δ T =  (  6 × 10² ) × 4.2 × 20 × 10⁻² / 60 ×  0.2 × 4.2

= >  Δ T =  ( 10² ) × 4.2 × 2 × 10⁻² /  0.2 × 4.2

= > Δ T = 2 /  0.2 C

= > Δ T = 10 C

Therefore , difference in temperatures is 10 C.