Chemistry, asked by meghakatiyar1, 11 months ago

Calculate the difference of heat of reaction at constant pressure and that at constant volume for the combustion of two moles of liquid benzene at 25°C.​

Answers

Answered by Anonymous
4

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2C6H6+15O2-------->12CO2+6H2O

⚠️n=12-15=-3

⚠️H=⚠️E+⚠️nRT

⚠️H-⚠️E=⚠️nRT

=>-3x8. 314x10^-3x298

= - 7.4kJ

Answered by Anonymous
0

Answer:

2C6H6+15O2-------->12CO2+6H2O

n=12-15=-3

H=️E+️nRT

️H-️E=nRT

=>-3x8. 314x10^-3x298

= - 7.4kJ

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