Question

Calculate the dimension of permittivity of free space

Answer 1

Answer:

Explanation:

The constant of a free space known as permittivity and has a value equal to 8.85 \times 10^{-12} farad per meter.

The dimension is $\left[M^{-1} L^{-3} T^{4} A^{2}\right]$

Answer 2

M^-1 L^-3 T^4 A^2 is the dimensional formula for permittivity of vacuum. Here M is Mass, L is length, T is time and A is current.

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