Question

calculate the dimensionsional formula for universal gravitational constant

Answer 1

$\boxed{\green{\mathsf{ Answer}}}$

$G = \bold{[{M}^{-1} {L}^{3}{T}^{-2}]}$

$\boxed{\green{\mathsf{ Explanation}}}$

Gravitational Constant:

• Let us,know about Gravitational force($F_G$)

$\boxed{\pink{\mathsf{ F_G = \dfrac{Gm_1 m_2}{{r}^{2}}}}}$

$F_G : \blue{\texttt{Gravitational\: Force}}$

$m_1, m_2 : \blue{\texttt{masses}}$

$r : \blue{\texttt{radius\: of\: the\: body}}$

$G : \blue{\texttt{Gravitational\: constant}}$

Units:

$\red{\bold{{kg}^{-1} {m}^{3}{s}^{-2}}}$

Dimensional Formula:

$\boxed{\pink{\mathsf{ F_G = \dfrac{Gm_1 m_2}{{r}^{2}}}}}$

$\green{\bold{[ML{T}^{-2}] = \dfrac{G [{M}^{2}]}{[{L}^{-2}]}}}$

$G = \green{\bold{[{M}^{-1} {L}^{3}{T}^{-2}]}}$

#$\texttt{\red{ ARAVIND}\: \blue{REDDY}....!}$