Calculate the discrimination (D) of the following quadratic equation. i) 5=2x-3x^2
Answers
Answer:
2 x^2 - 3x + 5 = 0
Where,
a = 2
b = -3
c = 5
[ According to ax^2 + bx + c = 0 , we just compared the equation with this]
Now, we know,
D = b^2 - 4ac
D = (-3)^2 - 4 × 2 × 5
D = 9 - 8 × 5
D = 9 - 40
D = - 31
Now, we know,
If D is less than 0 ( D < 0 ) then no real roots exist.
Step-by-step explanation:
Answer:
okk bhot bda iş e dekh kar smaj len ummid ha mujhe ki thik hoga
Step-by-step explanation:
Page No 34:
Question 1:
Write any two quadratic equations.
ANSWER:
Two quadratic equations are
x2+10x-200=0 and x2+5x-6=0.
Page No 34:
Question 2:
Decide which of the following are quadratic equations.
(1) x2 + 5x – 2 = 0
(2) y2 = 5y – 10
(3) y2+
1
y
=2
(4) x+
1
x
=-2
(5) (m + 2) (m – 5) = 0
(6) m3 + 3m2 – 2 = 3m3
ANSWER:
(1) x2 + 5x – 2 = 0
Only one variable x.
Maximum index = 2
So, it is a quadratic equation.
(2) y2 = 5y – 10
Only one variable y.
Maximum index = 2
So, it is a quadratic equation.
(3) y2+
1
y
=2
⇒y3+1=2y
Only one variable y.
Maximum index = 3
So, it is not a quadratic equation.
(4) x+
1
x
=-2
⇒x2+1=-2x
Only one variable x.
Maximum index = 2
So, it is a quadratic equation.
(5) (m + 2) (m – 5) = 0
⇒m2-3m-10=0
Only one variable m.
Maximum index = 2
So, it is a quadratic equation.
(6) m3 + 3m2 – 2 = 3m3
Only one variable m.
Maximum index = 3
So, it is not a quadratic equation.