Question

Calculate the displacement caused by the force in
horizontal direction when force of 800 N is acting
at an angle of 30° to the horizontal and does a
work of 80,000 J.
(Cos30=3^-1/2)

Answer 1

Solution :

⇒Given :

work done by force,W =80,000J

Force ,F= 800N

Angle between force and horizontal ,θ=30°

⇒To Find :

Displacement caused by the force

in horizontal direction.

Theory :

Work done by the by the force is measured by the product of magnitude of force and the displacement of the point of application in the direction of force.

${\purple{\boxed{\large{\bold{W=F.S}}}}}$

Step by step explanation:

we have to find the displacement caused by the force in horizontal direction.

We know W = F.s

⇒W=F×S ×cosθ

Now put the given values

$\implies80000 = 800 \times s \times\frac{ \sqrt{3} }{2}$

$\implies \: s = \frac{80000 \times2}{800 \sqrt{3}}$

$\implies \: s =\dfrac{200}{\sqrt{3}}m$

$s=\dfrac{200\times\sqrt{3}}{3}$

Therefore,

Displacement caused by the force

in horizontal direction is 66.6√3 m.

________________________

Additional information:

1. Work done is a scalar quantity.
2. Work done can be postive, negative and zero
3. SI Unit of work done is Joule.
4. CGS unit of work is erg .