Question

Calculate the distance and the displacement of the minute hand of a clock on moving from 10 p.m. to 11.15 p.m. The length of the minute hand of the clock is 14 cm.

please give appropriate answers.​

Answer 1

Answer:

Given that,

Time t=30 min=1800 sec

Now, the length of the minute hand is almost as long as the radius of the clock

The displacement is

D=2×4.5

D=9cm

D=0.09m

Now, the velocity is

v=

t

D

v=

1800

0.09

v=5×10

−5

m/s

Hence, the average velocity is 5×10

−5

m/s

Displacement during 6:00 AM to 6:30 PM will be:

D=4.5×2=9cm

D=0.09 m

Time taken:

t=12.5 Hours.

t=12.5×3600 sec

Therefore,

Velocity will be given by:

v=

12.5×3600

0.09

=2×10

−6

m/s

Explanation:

Hope it helps!!!

Answer 2

Answer:

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