Calculate the distance at which an object should be placed in front of a convex lens of focal length 100cm to obtain an erect image of double it's size
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let size of image be 2h cm and size of object be h cm
we know that,
h2/h1=v/u
2h/h=v/u
v=2u. eq:-(i)
given, f=100 cm
by lens formula
1/f=1/v-1/u
1/100=1/2u-1/u. from -i
1/100=-1/2u
-2u= -100
therefore u=50 cm
hence object distance is 50cm
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