Question

calculate the distance between A(5,-3) and B on the y axis whose ordinate is 9​

Answer 1

Answer: Solñ

A (5,-3) , B ( 0,y)

distance of AB = √(x2-x1)² + ( y2-y1 )²

9 = √(0-5)² + (y-(-3))²

9 = ✓25 + (y+3)²

9 =√25+y²+9+6y

9 = √34+y²+6y

Squaring both side

=> (9)² = (√34+y²+6y)²

=>81 = 34 + y² + 6y

=>81-34 = y²+6y

=>y²+6y-47=0