Question

Calculate the distance between A(7,3) and B on the axis whose abscissa is 11.

Answer 1

Distance = 5 units
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Answer 2

Answer:

The distance between A and B is 5 units.

Step-by-step explanation:

It is given point B on the axis whose abscissa is 11. It means the coordinates of B is (11,0).

The distance formula is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The distance A(7,3) and B(11,0).

$d=\sqrt{(11-7)^2+(0-3)^2}$

$d=\sqrt{(4)^2+(-3)^2}$

$d=\sqrt{16+9}$

$d=\sqrt{25}$

$d=5$

Therefore the distance between A and B is 5 units.