Question

Calculate the distance between A (7,3) and B on the
QC- axis whose abscissa is ll.​

Answer 1

Answer:

5 units

Step-by-step explanation:

We know that any point on x-axis has co-ordinates of the form(x, 0)

Abscissa of point B = 11

Since, B lies of of x-axis, so its co-ordinates are (11,0)

AB = 'sqrt((11-7)^2+(0-3)^2)'

= 'sqrt(16+9)'

= 'sqrt(25)'

= 5 units

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