Question

calculate the distance between A(7,5) and B on the x axis whose absicssa is 11
​

Answer 1

AnswEr:-

Your answer is 6.4 units.

Given Coordinates:-

• A(7,5) and B lies on x-axis with absicssa 11.

To Find:-

• The distance between point A and B.

Concepts Used:-

• Absicssa refers to the coordinate on x-axis.

Formula Used:-

• Distance Formula:-

$\tt\longrightarrow Distance = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$

Where,

• $\tt x_1 \:\:And\:\: x_2$ are x coordinates of two given points.

• $\tt y_1\:\:And\:\:y_2$ Are the y Coordinates of the given points.

So Here,

• $\tt x_1 \:\:And\:\: x_2$ Are 7 and 11 respectively.

• $\tt y_1 \:\:And\:\: y_2$ Are 5 and 0 respectively.

But why the y coordinate of B is zero??

This is because B lies on x-axis so its y coordinate must be zero thus its coordinate will be B(11,0).

So lets put the values in above formula:-

$\tt\mapsto Distance = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\\ \\ \tt\mapsto Distance= \sqrt{(11 -7)^2+(0-5)^2}\\ \\\tt\mapsto Distance = \sqrt{(4)^2+(-5)^2} \\ \\ \tt\mapsto Distance = \sqrt{16+25} \\ \\ \tt\mapsto Distance = \sqrt{41} \\ \\ \tt\mapsto Distance = 6.40 \:\:units.\:\:(Approx).$

$\tt\therefore$ Distance Between A and B is 6.4 units.