calculate the distance between athlete a and athlete b at the instance when athlete b starts to run
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11th
Physics
Motion in a Straight Line
Problems on Equation of Motion
An athlete runs a distance ...
PHYSICS
An athlete runs a distance of 1500 m in the following manner. (i) Starting from rest, he accelerates himself uniformly at 2 ms
−2
till he covers a distance of 900 m. (ii) He, the run remaining distance of 600 cm at the uniform speed developed. Calculate the time taken by the athlete to cover the two parts of the distance covered. Also find the time, when he is at the centre of the track.
MEDIUM
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CALCULATOR
Enter the know values to find unknown
Acceleration
Distance
Final Velocity
v = u + a*t
Initial Velocity u
m/s
Final Velocity v
m/s
Time t
s
Acceleration a
m/s²
RESET VALUES
ANSWER
The situation is shown in Fig.
Fig.
For motion between times t=0 and t
2
:
u=0,a=2 ms
−2
,s=900 m,v=v
2
(say)
As v
2
−u
2
=2as
∴v
2
2
−0
2
=2×2×900 or v
2
=60 ms
−1
Time, t
2
=
a
v−u
=
2
60−0
=30 s.
For motion between times t
2
and t
3
: This motion ???? at a constant speed of 60 ms
−1
.
∴ Time taken, t
3
−t
2
=
60
1500−900
=10 s
For motion between time t=0 and t
1
:
u=0,s=750 m,a=2 ms
−2
,t=t
1
(say)
As s=ut+
2
1
at
2
∴750=0×t
1
+
2
1
×2×t
1
2
t
1
=
750
=27.4 s.