Question

Calculate the distance covered by a free falling body durin first second of its motion?

Answer 1

distance covered in nth second is given by,
$s = u + \frac{a}{2} (2n - 1)$
in this case ,

u=0 m/s
a=g m/s²
n= 1 s
$s = 0 + \frac{g}{2} (2 - 1) \\ s = \frac{g}{2} \\ s = 4.9 \: m$
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Answer 2

5 m is travelled in first second