Question

calculate the distance of image(v) when the position of the object is 30 cm position of image is beyond c and it is enlarged its nature is real and inverted in concave mirror focal lenth is 20 cm​

Answer 1

Answer:

The Physics Classroom

A concave mirror with a focal length of 10.0 cm creates a real image 30.0 cm ... the image is real, inverted, enlarged in size, and located beyond 

Answer 2

ANSWER:

Given:

The radius of curvature (R)=20cm

Object distance(u) = 30cm

Image distance(v) = ?

Formula used:

$f = \frac{R}{2} \frac{1}{v} + \frac{1}{u} = \frac{1}{f}$

Calculation:

$f = \frac{R}{2}$

$f = \frac{20}{2}$

$f = 10cm$

$\frac{1}{v} + \frac{1}{u} = \frac{1}{f} \\ \frac{1}{v} = \frac{1}{f} - \frac{1}{u}$

$\frac{1}{v} = \frac{1}{10} - \frac{1}{30}$

$\frac{1}{v} = \frac{3 - 1}{30}$

$\frac{1}{v} = \frac{2}{30}$

$\frac{1}{v} = \frac{1}{15}$

$v = \frac{1}{1 \times 15}$

$v = \frac{1}{15}$

HOPE IT IS HELPFUL FOR YOU.