Question

calculate the distance of point (3,4) from origin . calculate the distance between point p (2,-3) & = (5,-7)​

Answer 1

Answer:

5

Step-by-step explanation:

A = (3,4), B = (0,0)

Distance = √(3-0)²+(4-0)²

√9+16

√25

5, only positive 5 would be taken as Distance is always Positive

P(2,-3) and Q(5,-7)

distance = √(2-5)²+(-3+7)²

√9+16

√25

5, only positive 5 would be taken as Distance is always Positive.

Answer 2

Answer:

1) Distance of (3,4) from origin = 5 units

2) Distance between (2, -3) and (5, -7) = 5 units

Step-by-step explanation:

1) We have to calculate distance from origin, the co-ordinates of origin is (0,0)

Let the points be A(3, 4) and B(0,0)

AB =  $\sqrt{(0-4)^{2} + (0-3)^{2}}$

     = $\sqrt{16 + 9}$ = $\sqrt{25}$

     = 5 units

Therefore, distance of (3,4) from origin is 5 units.

2) Let the points be P(2, -3) and Q(5, -7)

PQ = $\sqrt{(5-2)^{2} + (-7 + 3)^{2}}$

     = $\sqrt{9 + 16}$ = $\sqrt{25}$

     = 5 units

Therefore, distance between (2, -3) and (5, -7) is 5 units.

In both cases, for the square root of 25, (+5) is taken as distance is always positive.

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