Calculate the distance travel by a freely falling body in the 5^th second of its fall
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Answer:
44.1m
Explanation:
S of nth = u + 1/2* a(2n-1)
S of 5th = 0 + 1/2 * 9.8(2*5-1)
= 1/2* 9.8(9)
= 1/2* 88.2
= 44.1m
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