Physics, asked by shobha3168, 11 months ago

Calculate the distance travel by a freely falling body in the 5^th second of its fall

Answers

Answered by tom77
0

Answer:

44.1m

Explanation:

S of nth = u + 1/2* a(2n-1)

S of 5th = 0 + 1/2 * 9.8(2*5-1)

= 1/2* 9.8(9)

= 1/2* 88.2

= 44.1m

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