Calculate the distance travelled and net displacement of the object moving along a circular path of radius “r” when it completes one quarter of a round.
Answers
Answer:
Displacement is shortest distance between starting point and end point.
Distance is path length covered by particle.
When particle moves along half circle, it covers half the circumference therefore distance covered is (2×pi×r)/2 = pi× r. Where r is radius of circle.
When particle covers half the circle, it is diametrically opposite to the starting point of its motion.
Therefore shortest distance is equal to diameter of circle or 2× r is a displacement.
Hence displacement is equal to diameter or 2 times the radius of circle.
Hope this will clear the concept.
This question will be more clear to you if you make a circle .
The distance should be half the circumference of circle which is 2πr/2
Distance = πr
The displacement is the shortest distance .
The shortest distance will be the diameter.
Displacement = diameter = 2r
Hope this helps!
Explanation:
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