Question

calculate the distance travelled by the body in first 4 seconds​

Answer 1

Answer:

Distance = Area under the graph  (Triangle)

Area of Triangle = bh/2

b = 4

h = 4

Therefore, 4*4/2 = 8

Hence the distance is 8m

Answer 2

Answer:

8m

Step-by-step explanation:

Acceleration=

$\frac{dv}{dt} = \frac{4}{4}$

Hence acceleration is 1m/sec^2

using the equation

$s = ut + \frac{1}{2} a {t}^{2}$

where

$u = 0$

$t = 4$

$a = 1$

we have

$s = 0 \times 4 + \frac{1}{2} \times 1 \times {4}^{2}$

Therefore

$s = 8m$