calculate the distance upto which ray optics is a good approximation for light of wavelength 500nm falls on an aperture of width 5mm
Answers
Answered by
3
Explanation:
Aperture Width a=4mm
Fresnel distance, Z
F
=
λ
a
2
=
500×10
−9
(4×10
−3
)
2
∴z
p
=32m
Answered by
1
Explanation:
width a= 5×10^-3
wavelength= 500×10^-9
Fresnel dist. Z= a^2÷ 2×wavelength
= (5×10^-3)^2 ÷ 2×500 ×10^-9
= 25×10^-6 ÷ 1000× 10^-9
= 0.025 ×10^3
= 25 m
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