Question

calculate the distence covered by a car which is moving the speed of 10.5 m/s , in 15minute. also calculate speed of the car in km/h.​

Answer 1

Answer:

first we change 15min into sec=900sec now we apply formula d=st d=10.5×900=9450 m we change speed into km/hr 10.5×5/18=52.5/18=2.916 km/hr approximately

Answer 2

$\orange{\mathrm{\mathrm{\underline{Required\: Answer\: :-}}}}$

$\huge\boxed{\boxed{\boxed{\boxed{\boxed{S = 9.45 km}}}}}$

Explanation:-

$\green{\mathrm{\mathrm{Speed = 10.5 m/s}}}$

$\green{\mathrm{\mathrm{Time = 15 minutes}}}$

$\gray{\mathrm{\mathrm{To\: calculate\: the\: distance\: travelled.}}}$

$\gray{\mathrm{\mathrm{v = 10.5 m/s \: T = 900 s}}}$

$\red{\mathrm{\mathrm{By\: using \:Distance\: formula:- }}}$

$\huge\pink{Distance = Speed \times time }$

$\blue{\mathrm{\mathrm{put\: the \:given\: value }}}$

→$\mathsf{Distance =\dfrac{105}{10}\times 900}$

$\gray{\mathrm{\mathrm{Distance = 9450 m \:9.45 km}}}$

hence,

$\gray{\mathrm{\mathrm{\text{Distance travelled will be 9.45 km}}}}$

• For calculating the speed in to km / hr.

$\gray{\mathrm{\mathrm{Multiply \: the \: speed \: by\: eighteen \: upons \: five.}}}$

→$\mathsf{\dfrac{105}{10}\times \dfrac{18}{5}}$

→$\mathsf{\dfrac{378}{10}}$

→$\mathsf{37.8 km/hr}$