Math, asked by 1404anukriti, 1 month ago

Calculate the drift velocity of free electrons if a current of 5 A is maintained in a conductor of cross-section 10-2m2 . The number density of free electrons is 5 × 1020m-3 .​

Answers

Answered by mad210201
1

Given:

current =5 A

Area of cross section=10^{-2} m^{2}

The density of free electrons=5\times10^{20} \ m^{-3}

To find:

drift velocity of free electrons

Step-by-step explanation:

drift velocity of free electrons

=\dfrac{current}{number\ density\ of\ electrons\times charge\ on\ electron\times Area}\\=\dfrac{5}{5\times10^{20}\times1.6\times10^{-19}\times 10^{-2} }\\=6.25\ ms^{-1}

The drift velocity of free electrons is 6.25\ ms^{-1}

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