Question

Calculate the e.m.f. of the cell,
Mg/Mg2+ (0.1 M) || Ag+ (1.0 x 10^3 M)/Ag
The values of E Mg2+ /Mg
and E
2.37 V and + 0.80 V respectively.

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Answer 1

Given:

Mg/Mg2+ (0.1 M) || Ag+ (1.0 x 10^3 M)/Ag. The values of E Mg2+ /Mg  and E  2.37 V and + 0.80 V respectively

To find:

Calculate the e.m.f. of the cell

Solution:

From given, we have,

Mg/Mg2+ (0.1 M) || Ag+ (1.0 x 10^3 M)/Ag.

The values of E Mg2+ /Mg  and E  - 2.37 V and + 0.80 V respectively

The emf of the cell is given by the formula,

E° cell = E° cathode - E° anode

From given, we have,

E° cathode = 0.80 V

E° anode = - 2.37 V

thus substituting the given values in the above equation, we get,

E° cell = 0.80 - (- 2.37)

= 0.80 + 2.37

∴ The e.m.f. of the cell, E° cell = 3.17 V