Question

calculate the e.m.f of the cell zn(s)|zn2+(1m)||cu2+(1m)|cu(s)E°(cu2+)cu)=0.34v and E°(zn2+)zn)=-0.76v?​

Answer 1

Answer:

       E= E' -0.0592/n( log cu+2/zn+2)

Explanation:

E'= 0.34-(-0.76)

=1.1

E= 1.1-0.0592/2(log 1/1)

=1.1-0.0592\2

=1.1-0.0296

=1.0704 volt