Question

Calculate the e.m.f of the following cell : Cd | Cd2+ (0.01M) || H+ (0.02M) | Pt , H2 (0.8 atm). Given: E° (Cd2+ | Cd ) = -0.40 V and log (0.01×0.8)/ (0.02)^2 = 1.3010
5 points
0.56 V
0.66 V
0.36 V
0.12 V

Answer 1

Answer:

sorry don't know the answer

Explanation:

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