Question

Calculate the EAN for the following complexes
1 . K2[PtCl6]
2 .[Co(en)3]2(SO4)3​

Answer 1

Answer:

1.$K^{2} [PtCl^{6} ]$

The oxidation state of platinum:-

 Pt + Cl x 6 = - 2

 Pt +(- 1 x 6) = - 2

 Pt - 6 = -2

 Pt = -2+6

 Pt = 4

EAN = Atomic number - Oxidation number + Coordination number x 2)

EAN = 78 - 4 +(6x2)

EAN = 74+12

EAN = 86

2.$[Co(en)^{3} ]^{2} 2(SO4)^{3}$

The oxidation state of platinum:-

 Co + (en) x 3  = 3

 Co + (0 x 3) = 3

 Co = 3

EAN = Atomic number - Oxidation number + Coordination number x 2)

EAN =27 - 3 +(6x2)

EAN = 24+12

EAN =36

       

Answer 2

Explanation:

Given -

1. K2[PtCl6]
2. [Co(en)3]2 (SO4)3

To Find -

• EAN

As we know that :-

• EAN = Z - O.N. + C.N. x 2

here,

Z = atomic number

O.N. = oxidation number

C.N = Co-ordinarion number

In Q1)

K2[PtCl6]

Atomic number of Central atom (Pt) = 78

O.N. of central atom (Pt) =

→ 2 × 1 + x - 1 × 6 = 0

→ x = 4

C.N = no. of ligan × denticity

→ 6 × 1

→ 6

Now,

EAN = 78 - 4 + 6 × 2

→ 78 - 4 + 12

→ 90 - 4

→ 86

In Q2)

[Co(en)3]2 (SO4)3

Atomic number of Co = 27

oxidation number of Co =

→ x + 0×3 = 3

→ x = 3

Co-ordinarion number =

→ 3 × 2

→ 6

Now,

EAN = 27 - 6 + 6 × 2

→ 27 - 3 + 12

→ 39 - 3

→ 36

Hence,

EAN of K2[PtCl6] is 86

And

EAN of [Co(en)3]2 (SO4)3 is 36