Calculate the earths magnetic field at a place where angle of dip 50 degree and horizontal component of earths magnetic field is 0.3G
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Answer:
Explanation:
Given that,
Total strength of field B=0.5G,
Horizontal component of the field H=0.3G,
Total strength of field is given by
B=
(H
2
+V
2
)
where, V is the vertical component of the field.
B
2
=H
2
+V
2
V
2
=B
2
−H
2
=(0.5)
2
−(0.3)
2
=0.4G
Now, angle of dip is
tanδ=
H
V
=
0.3
0.4
=
3
4
δ=tan
−1
3
4
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