Question

calculate the effective capacitance between A and B from the figure given below c1= c3 = 100uf, c2= c4= 200uf​

Answer 1

When a battery is applied across A and B, then the points b and c will be at the same potential (∵C

1

=C

4

=C

3

=C

5

=4μF)

Therefore, no charge flows through C

2

.

As, C

1

and C

5

are in series.

∴ Their equivalent capacitance,

C

′

=

C

1

+C

5

C

1

×C

5

=

4+4

4×4

=2μF

Similarly, C

4

and C

3

are in series. Therefore, their equivalent capacitance

C

′′

=

C

3

+C

4

C

3

×C

4

=

4+4

4×4

=2μF

Now, C

′

and C

′′

are in parallel. Therefore, effective capacitance between A and B

=C

′

+C

′′

=2+2=4μF

Answer 2

Answer:

2+2=4uF is the correct answer