Question

Calculate the effective resistance between A and B in the circuit given below:
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Answer 1

Answer:

3 ohm

Explanation:

Resistance -

In series - 4+6=10ohm

In series - 3+3=6ohm

In parallel - 1/10+1/15+1/6 = 3+2+5/30 = 10/30 = 1/3

Therefore, equivalent resistance = 3 ohm

Answer 2

Answer:

The effective resistance between A and B in the circuit is 0.33 ohms.

Explanation:

We have to calculate the effective resistance between A and B in the given circuit.

1) Resistance of 4 ohms and 6 ohms are connected in series:

$=4+6\\=10ohms$

2) Resistance of 3 ohms and 3 ohms are connected in series:

$=3+3\\=6ohms$

3) Now, we can see that Resistance of 10 ohms, 15 ohms and 6 ohms are connected in parallel:

$=\frac{1}{10}+\frac{1}{15}+\frac{1}{6} \\=\frac{3+2+5}{30}\\ =\frac{10}{30}\\ =\frac{1}{3} ohm$

Therefore, the effective resistance between A and B in the circuit is 0.33 ohms.