calculate the effective resistance between the point A and B in the network shown in the figure....
I want both the answer..if possible
then...u can only...give the 2nd figure tht is..the square one..plz answer
Attachments:
Answers
Answered by
17
Answer:
Explanation:
FIG 1:
1 OHM AND 2 OHM ARE IN SERIES.
R SERIES = 1+2 = 3 OHMS.
THIS 3 OHM AND 1.5 OHM ARE IN PARALLEL.
R NET = 3*1.5/3+1.5
= 4.5/4.5
= 1 OHMS.
THEREFORE THE NET RESISTANCE IN THE FIRST CIRCUIT IS 1 OHM
FIG 2:
THIS CIRCUIT REPRESENTS A BALANCED WHEASTONE'S BRIDGE.
3/3 = 2/2 = 1.
THEREFORE NO CURRENT FLOWS THROUGH THE 1 OHM CIRCUIT
THEREFORE THE RESISTORS 3 AND 2 ARE IN SERIES IN ACB PATH AS IN SIMILAR IN PATH ADB.
R SERIES = 3+2
= 5 OHMS.
THIS 5 OHM IN ACB AND THE OTHER 5 OHM IN ADB ARE IN PARALLEL.
R NET = 5*5/5+5
= 25/10
=2.5 OHMS.
THEREFORE THE NET RESISTANCE IN THE SECOND CIRCUIT IS 2.5 OHMS.
HOPE THIS HELPS.
Similar questions