Question

Calculate the effective resistance between the points A and B in the network shown below in figure.​

Answer 1

Your answer is ready Dear........ (9 Ohm)

Hope it was helpful for you buddy.....

Answer 2

Between points A and B the resistance are in two ways i.e. In Parallel Combination and in Series combination. So at first we will find the resistance in parallel combination then we will find in series combined.

In Parallel Combination,

$\dfrac{1}{{R}_{P}} = (\dfrac{1}{12} + \dfrac{1}{6} + \dfrac{1}{4} )\: ohm$

$\dfrac{1}{{R}_{P}} = \dfrac{6}{12} \:$

${R}_{P} = 2 \: Ohm$

Now in Series Combination,

${R}_{S} = {R}_{1} + {R}_{P} + {R}_{3}$

${R}_{S} = (2 + 2 + 5) \: Ohm$

${R}_{S} = 9 \: \: Ohm$

Hence, the effective resistance between point A and B = Rs = 9 Ohm.