Question

Calculate the efficiency of Carnot's engine
Operating between 300 °C and 100°C​

Answer 1

Answer:

• Efficiency of the Carnot's engine is 34.90%

Step-by-step explanation:

According to the Question

It is given that ,

• $T_1$ = 300°C
• $T_2$ = 100°C

Conversion of Unit

$T_1$ = 300 + 273 = 573K

$T_2$ = 100 + 273 = 373K

Now, calculating the effeciency of carnot engine

Efficiency of carnot engine is calculated by

$\boxed{\bf{\eta= 1 -\frac{T_2}{T_1}}}$

by putting the value we get

$\sf\implies\eta = \sf\; 1 - \frac{373}{573} \\\\\sf\implies\eta = \sf\; \frac{573-373}{573} \\\\\sf\implies\eta = \sf\frac{200}{573} \\\\\sf\implies\eta = \sf\frac{200}{573} \times 100\\\\\sf\implies\eta = \sf\frac{20000}{573} \\\\\sf\implies\eta = \sf\; 34.90\%\\\\\boxed{\bf{Hence, the ~ efficiency ~ of ~ the ~ carnot ~ engine ~ is~ 34.90\%}}$