Question

calculate the efficiency of carnot's engine working between 227°C and 15°C​

Answer 1

Answer:

42.4%

Explanation:

T₁ = 15° C

    = (15 + 273) K

     = 288K

T₂ = 227° C

    = (227 + 273)K

    = 500 K

η = ( 1 - T₁/T₂) * 100

    = (1 - 288/500) * 100

    = 212/5  = 42.4%

Answer 2

Answer:

The efficiency of carnot's engine working between 227°C and 15°C​ is 0.424

Concept:

Efficiency of Carnot's engine is given by,

η = 1 - (T₂/T₁)

where η = Efficiency of the engine

T₁ = Source temperature

T₂ = Sink temperature

Given:

Source temperature, T₁ = 227°C = (227 + 273) K = 500 K

Sink temperature, T₂ = 15°C = (15 + 273)K = 288 K

Find:

Efficiency of the Carnot engine.

Solution:

As we know,

η = 1 - (T₂/T₁)

η = 1 - (288/500)

η = (500 - 288)/500

η = 212/500

η = 0.424

Hence, the efficiency of the Carnot's engine, η = 0.424.

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