Calculate the efficiency of packing in case of a metal crystal for (i) simple cubic (ii) body-centred cubic (iii) face-centred cubic (with the assumptions that atoms are touching each other).
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for finding packing efficiency we have require :
1. area occupied by all atoms /ions in unit cell
2. total area of unit cell.
because
(i)
if edge length = a
then, atmic radius , r = a/2
volume of unit cell , V = a³
volume of all atoms in a unit cell, v = 4/3π(a/2)³
= πa³/6
so, packing efficiency = v/V = π/6 = 0.52 or 52%
(ii)
if edge length = a
atomic radius , r = √3a/4
volume of unit cell, V = a³
number of atoms per unit cell = 2
volume of all atoms in a unit cell = 2 × 4/3 π(√3a/4)³ = 4/3 πa³× 3√3/64 = √3πa³/8
so, packing efficiency = √3π/8 = 0.68 or 68%
(iii)
if edge length = a
atomic radius , r = a/2√2
volume of unit cell, V = a³
number of atoms per unit cell = 4
volume of all atoms in a unit cell , v = 4 × 4/3π(a/2√2)³ = πa³/3√2
so, packing efficiency = π/3√2 = 0.74 or 74 %
1. area occupied by all atoms /ions in unit cell
2. total area of unit cell.
because
(i)
if edge length = a
then, atmic radius , r = a/2
volume of unit cell , V = a³
volume of all atoms in a unit cell, v = 4/3π(a/2)³
= πa³/6
so, packing efficiency = v/V = π/6 = 0.52 or 52%
(ii)
if edge length = a
atomic radius , r = √3a/4
volume of unit cell, V = a³
number of atoms per unit cell = 2
volume of all atoms in a unit cell = 2 × 4/3 π(√3a/4)³ = 4/3 πa³× 3√3/64 = √3πa³/8
so, packing efficiency = √3π/8 = 0.68 or 68%
(iii)
if edge length = a
atomic radius , r = a/2√2
volume of unit cell, V = a³
number of atoms per unit cell = 4
volume of all atoms in a unit cell , v = 4 × 4/3π(a/2√2)³ = πa³/3√2
so, packing efficiency = π/3√2 = 0.74 or 74 %
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